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sqltreat
answered Nov 30 '-1 00:00
die() function do following job:1. die() function stop the execution of the script
2. die() function will print the string which passed as an argument in the die() function
die("I am in die function");
echo "i am after die function";
above code will print "i am in die function" but it will not run after code of die() function so it will not print or next statement
die(1);
if you pass the number as an argument to the die() function, it will only stop the script execution to that point but not print anything but it take number exit status