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swift
Asked 4 years ago
13 Jan 2020
Views 1393
noob

noob posted

Cannot invoke "jsonObject: with an argument list of type "(with: String, options: [Any])"

try to convert string json to object and i am getting following error
Cannot invoke "jsonObject: with an argument list of type "(with: String, options: [Any])"

 let    locationlist = UserDefaults.standard.value(forKey: "locationlist") as! String
        let json = try? JSONSerialization.jsonObject(with: locationlist, options: [])
        print(json)
Rasi

Rasi
answered Apr 25 '23 00:00

This error message suggests that you are trying to call a method named jsonObject with an argument list of type (wi th: String, options: [Any] ), but the method is not defined to take arguments of that type.

Without seeing the full code and context, it's difficult to provide a specific solution. However, here are a few possible explanations and solutions:

1.Typo or incorrect method signature: Make sure that the method name and signature match the method definition. Check that the method is defined with the correct parameter types and that you are passing the correct arguments.

2.Incorrect usage of JSON parsing methods: The jsonObject method is not a standard JSON parsing method in the Swift standard library or Foundation framework. Make sure you are using a valid JSON parsing method, such as JSONSerialization.jsonObject(with:options:) to parse JSON data into a dictionary or array.

Here's an example of how to use JSONSerialization.jsonObject to parse JSON data:



let jsonString = "{\"name\": \"John\", \"age\": 30}"
if let jsonData = jsonString.data(using: .utf8) {
    do {
        let jsonObject = try JSONSerialization.jsonObject(with: jsonData, options: [])
        if let dict = jsonObject as? [String: Any] {
            print(dict) // prints ["name": "John", "age": 30]
        }
    } catch {
        print("Error parsing JSON: \(error.localizedDescription)")
    }
} else {
    print("Invalid JSON string")
}

In this example, the JSON string is first converted to a Data object using the d ata(using: ) method. The JSONSerialization.jsonObject(with:options:) method is then used to parse the JSON data into a Swift object. The options parameter is set to an empty array [] to specify default parsing options.

It's important to note that the JSON string must be valid JSON for the parsing to work. If the JSON is malformed, the parsing will fail and an error will be thrown.

3.Third-party library conflict: If you are using a third-party library that defines a method named jsonObject , there may be a conflict with the method signature or parameter types. Make sure that the library is compatible with your code and that you are using the correct method signature and parameter types.
If none of these solutions work, please provide more context and code examples so we can better understand the issue.
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